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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T23:36:21+00:00 2026-06-14T23:36:21+00:00

In C language, I have an array[3][2]; int i = 0, j = 0;

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In C language,

I have an array[3][2];

int i = 0, j = 0;
for (i = 0; i < 3; i++) {
    for (j = 0; j < 2; j++) {
        printf("%d", array[i][j]);
    }
}

When I use gcc to compile .c file, the error shows:

format ‘%d’ expects argument of type ‘int’, but argument 2 has type ‘int *’

How to print an array using C?

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  1. Editorial Team
    Editorial Team
    2026-06-14T23:36:22+00:00Added an answer on June 14, 2026 at 11:36 pm

    The error message seems pretty straight forward. It’s telling you that array[i][j] is of type int*, while the printf() “%d” formatter is expecting an argument of type int.

    I’m not sure what you expect to happen here. You haven’t shown us how you declare array. But, if it’s supposed to be a two-dimensional array of int, then you declared it wrong.

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