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Home/ Questions/Q 3316608
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T22:29:23+00:00 2026-05-17T22:29:23+00:00

In C#, the following code doesn’t compile: class Foo { public string Foo; }

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In C#, the following code doesn’t compile:

class Foo {

    public string Foo;

}

The question is: why?

More exactly, I understand that this doesn’t compile because (I quote):

member names cannot be the same as their enclosing type

Ok, fine. I understand that, I won’t do it again, I promise.

But I really don’t understand why the compiler refuses to take any field having the same name as an enclosing type. What is the underlying issue that prevents me to do that?

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  1. Editorial Team
    Editorial Team
    2026-05-17T22:29:24+00:00Added an answer on May 17, 2026 at 10:29 pm

    Strictly speaking, this is a limitation imposed by C#, most likely for convenience of syntax. A constructor has a method body, but its member entry in IL is denoted as “.ctor” and it has slightly different metadata than a normal method (In the Reflection classes, ConstructorInfo derives from MethodBase, not MethodInfo.) I don’t believe there’s a .NET limitation that prevents creating a member (or even a method) with the same name as the outer type, though I haven’t tried it.


    I was curious, so I confirmed it’s not a .NET limitation. Create the following class in VB:

    Public Class Class1
        Public Sub Class1()
    
        End Sub
    End Class
    

    In C#, you reference it as:

    var class1 = new Class1();
    class1.Class1();
    
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