Home/ Questions/Q 8868425
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-06-14T17:16:06+00:00

In C++11: If I increment an atomic variable (operator ++ on std::atomic), is the

  • 0

In C++11:
If I increment an atomic variable (operator ++ on std::atomic), is the new value stored with a memory barrier? Or do I have to explicitly do a store?

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    You don’t need to do an explicit store. The sequential consistency memory ordering will be used.

    operator++(int) and operator++() on atomic<integral> types are specified to have the effect of fetch_add(1), which ends up calling the member function with the default memory ordering memory_order_seq_cst.

    For the spec look around Requirements for operations on atomic types [atomics.types.operations.req] 29.6.5/33

    • 0