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Home/ Questions/Q 6765107
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T14:40:24+00:00 2026-05-26T14:40:24+00:00

In C++11 you can use a range-based for , which acts as the foreach

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In C++11 you can use a range-based for, which acts as the foreach of other languages. It works even with plain C arrays:

int numbers[] = { 1, 2, 3, 4, 5 };
for (int& n : numbers) {
    n *= 2;
}

How does it know when to stop? Does it only work with static arrays that have been declared in the same scope the for is used in? How would you use this for with dynamic arrays?

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  1. Editorial Team
    Editorial Team
    2026-05-26T14:40:24+00:00Added an answer on May 26, 2026 at 2:40 pm

    It works for any expression whose type is an array. For example:

    int (*arraypointer)[4] = new int[1][4]{{1, 2, 3, 4}};
    for(int &n : *arraypointer)
      n *= 2;
    delete [] arraypointer;
    

    For a more detailed explanation, if the type of the expression passed to the right of : is an array type, then the loop iterates from ptr to ptr + size (ptr pointing to the first element of the array, size being the element count of the array).

    This is in contrast to user defined types, which work by looking up begin and end as members if you pass a class object or (if there is no members called that way) non-member functions. Those functions will yield the begin and end iterators (pointing to directly after the last element and the begin of the sequence respectively).

    This question clears up why that difference exists.

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