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Home/ Questions/Q 7194407
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T20:21:54+00:00 2026-05-28T20:21:54+00:00

In Clojure, what is the best way for iterating concurrently on two seqs and

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In Clojure, what is the best way for iterating concurrently on two seqs and calling a function on the two running elements?
For example:

(def a (range 3))
(def b (range 100 103))
(defn my-func [] ...) ;some custom code

The code should execute my-func 3 times, like this:

(my-func 0 100)
(my-func 1 101)
(my-func 2 102)

How can I achieve that without defining any function or macro?

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  1. Editorial Team
    Editorial Team
    2026-05-28T20:21:55+00:00Added an answer on May 28, 2026 at 8:21 pm

    map is exactly what you need, it takes a function and any number of seqs and calls them just as you wish.

    (def a (range 3))
    (def b (range 100 103))
    user=> a
    (0 1 2)
    user=> b
    (100 101 102)
    
    user=> (defn my-func [a b] (str a ":" b))
    #'user/my-func
    
    user=> (my-func 1 2)
    "1:2"
    
    user=> (map my-func a b)
    ("0:100" "1:101" "2:102")
    

    and because map is lazy if you want the function to actually run now:

    (doall (map my-func a b))
    
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