Question

In database, Student_id is containing 0 value. I want to check it in if condition, but required result is not achieved. I have tried following scenarios in if condition:

if(is_null($item['student_id'])) {}

if($item['student_id'] === 0){}

if($item['student_id'] == 0){}

if(intval($item['student_id']) == 0){}

if(strval("$item['student_id']") == "0"){}

Note: Currently Iam trying to print some message in if conditions. But on student_id = 0, nothing is printed. If student_id is other than 0, then print is working fine.

Can some one guide me what Iam doing wrong and how it can be rectified.

I have added var_dump

    array
  '_id' => 
    object(MongoId)[2]
      public '$id' => string '50906d7fa3c412bb040eb577' (length=24)
  'student_id' => int 0
  'type' => string 'exam' (length=4)
  'score' => float 54.653543636265
array
  '_id' => 
    object(MongoId)[6]
      public '$id' => string '50906d7fa3c412bb040eb578' (length=24)
  'student_id' => int 0
  'type' => string 'quiz' (length=4)
  'score' => float 31.950044967421
array
  '_id' => 
    object(MongoId)[2]
      public '$id' => string '50906d7fa3c412bb040eb579' (length=24)
  'student_id' => int 0
  'type' => string 'homework' (length=8)
  'score' => float 14.850457681164

Answer 1

This should work unless your value is not really 0.

if(intval($item['student_id']) == 0){}

Else another way that could work is this, you almost had it:

if($item['student_id'] === '0'){}

But then again, make sure you REALLY have a 0 in there… can you var_dump $item for us just to make sure?