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Home/ Questions/Q 8884099
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T20:58:56+00:00 2026-06-14T20:58:56+00:00

In Django, inside a template, I do {% url ‘Customer.views.edit_customer’ 1 %} and I

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In Django, inside a template, I do

{% url 'Customer.views.edit_customer' 1 %}

and I get a NoReverseMatch exception. However, in the line before the template render I do:

print reverse('Customer.views.edit_customer', args=(1,))

and it prints the expected URL. I know I can always just pass in the result of reverse, but I would like to understand what’s going on.

The url pattern is:

url(r'^customer/edit/(\d+)$', edit_customer),

Is there a way of doing the equivalent of the reverse call in the template?

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  1. Editorial Team
    Editorial Team
    2026-06-14T20:58:58+00:00Added an answer on June 14, 2026 at 8:58 pm

    If you are using Django 1.4, remove the quotes

    {% url Customer.views.edit_customer 1 %}
    

    see https://stackoverflow.com/a/4981105/44816

    Django 1.5 will accept quoted url matching patterns. You can load the url template tag from future, if you’d like to quote your patterns. Use the following before the first url tag in your templates

    {% load url from future %}
    
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