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Home/ Questions/Q 3339876
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T00:32:35+00:00 2026-05-18T00:32:35+00:00

In Firefox I suddenly got this message from firebug: $(‘a.close, #fade’).live is not a

  • 0

In Firefox I suddenly got this message from firebug:

$('a.close, #fade').live is not a function

Indeed, when I click the image gallery and popup displays. I cannot close out of it. The click event never registers due to this error message.

This is script:

        $('a.poplight[href^=#]').click(function() {
        var popID = $(this).attr('rel');  
        var popURL = $(this).attr('href');  

        var query= popURL.split('?');
        var dim= query[1].split('&');
        var popWidth = dim[0].split('=')[1];  

        //Fade in the Popup and add close button

        var div_popup = document.createElement('div');
        div_popup.setAttribute('id',popID);
        div_popup.setAttribute('class','popup_block');
        document.body.appendChild(div_popup);

        $(div_popup).fadeIn().css({ 'width': Number( popWidth ) }).prepend('<a href="#" class="close"><img src="close_pop.png" class="btn_close" title="Close Window" alt="Close" /></a> <a href="thumbBg' + $(this).attr('rel').substring($(this).attr('rel').lastIndexOf('p') + 1,$(this).attr('rel').length) + '"></a><p>The Human Diet: By Rene Endara</p>');

        var popMargTop = ($('#' + popID).height() + 80) / 2;
        var popMargLeft = ($('#' + popID).width() + 80) / 2;

        $('#' + popID).css({
            'margin-top' : -popMargTop,
            'margin-left' : -popMargLeft        
        });

        $('body').append('<div id="fade"></div>');  
        $('#fade').css({'filter' : 'alpha(opacity=80)'}).fadeIn(); 
        return false;
    });

    //Close Popups and Fade Layer
    $('a.close, #fade').live('click', function() {  
        $('#fade , .popup_block').fadeOut(function() {
            $('#fade, a.close').remove();  //fade them both out
        });
        return false;
    });

markup:

    <ul class="thumb">
    <li><a href="#?w=500" rel="popup1" class="poplight"><img src="images/thumb1.jpg" alt="" /></a></li>
    <li><a href="#?w=500" rel="popup2" class="poplight"><img src="images/thumb2.jpg" alt="" /></a></li>
    <li><a href="#?w=500" rel="popup3" class="poplight"><img src="images/thumb3.jpg" alt="" /></a></li>
    <li><a href="#?w=500" rel="popup4" class="poplight"><img src="images/thumb4.jpg" alt="" /></a></li>
   </ul>

Thanks for response.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T00:32:35+00:00Added an answer on May 18, 2026 at 12:32 am

    .live() was introduced in jQuery 1.3, therefore it won’t work with earlier versions.

    .live() has also since been deprecated in jQuery 1.7 onwards.

    The alternatives are .on() and .delegate()

    See related question jQuery 1.9 .live() is not a function on how to migrate existing code.

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