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Home/ Questions/Q 7718879
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T03:16:34+00:00 2026-06-01T03:16:34+00:00

In following template call <xsl:call-template name=My_Class> <xsl:with-param name=className select=getClassName()/> <xsl:with-param name=baseClassName select=??????/> </xsl:call-template> i

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In following template call

  <xsl:call-template name="My_Class">
    <xsl:with-param name="className" select="getClassName()"/>
    <xsl:with-param name="baseClassName" select="??????"/>
  </xsl:call-template>

i have to call My_Class template with value of second parameter i.e. baseClass as user defined. i.e. suppose i want call this template by passing value of second argument(shown as ???? in above code) as “balaji”.
Any suggestion on above? Thanks in advance.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T03:16:35+00:00Added an answer on June 1, 2026 at 3:16 am

    If you want to pass a parameter as a fixed, you can just do something like this:

    <xsl:call-template name="My_Class">
        <xsl:with-param name="className" select="getClassName()"/>
        <xsl:with-param name="baseClassName" select="'balaji'"/>
    </xsl:call-template> 
    

    Alternatively, you could specify the value as a default value in the template itself

    <xsl:call-template name="My_Class">
        <xsl:with-param name="className" select="getClassName()"/>
    </xsl:call-template> 
    
    <xsl:template name="My_Class">
       <xsl:param name="className" />
       <xsl:param name="baseClassName" select="'Balaji'" />
       <xsl:value-of select="$baseClassName" />
    </xsl:template>
    

    Is this what you are were looking for?

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