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Home/ Questions/Q 7765319
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T15:08:16+00:00 2026-06-01T15:08:16+00:00

In Go, if I define a function with pointer as the receiver, shouldn’t it

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In Go, if I define a function with pointer as the receiver, shouldn’t it allow call to the function from a pointer only? Why is it ok to call this function from the value itself and have the same effect.

For example, in following program: m1.reset() & m2.reset() have the same effect. Even though m1 is a value and m2 is a pointer.

I’m a bit confused as there are two ways of doing the same thing and am not sure which one to follow. Though most of the code follows the convention of calling the function using pointer field. Am I missing something?

package main

    import "fmt"

    type MyStruct struct {
        X int
    }

    func (m *MyStruct) reset() {
        m.X = 0
    }

    func main() {
        m1 := MyStruct{1}
        m2 := &MyStruct{1}

        fmt.Println(m1.X)
        fmt.Println(m2.X)

        m1.reset()
        m2.reset()

        fmt.Println(m1.X)
        fmt.Println(m2.X)
    }
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  1. Editorial Team
    Editorial Team
    2026-06-01T15:08:18+00:00Added an answer on June 1, 2026 at 3:08 pm

    Specs says:

    The method set of the corresponding pointer type *T is the set of all methods with receiver *T or T (that is, it also contains the method set of T).

    The next piece of necessary info about method calls says:

    A method call x.m() is valid if the method set of (the type of) x contains m and the argument list can be assigned to the parameter list of m. If x is addressable and &x’s method set contains m, x.m() is shorthand for (&x).m().

    Put the two above things together and you get the behavior you see.

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