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Home/ Questions/Q 8954591
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T14:20:33+00:00 2026-06-15T14:20:33+00:00

In have an SQL table like: id, parentid, name 1 0 Root 2 1

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In have an SQL table like:

id, parentid, name 
1     0        Root
2     1        label 1
3     2        label 1.1
4     3        label 1.1.1
5     1        label 2
6     5        label 2.1
7     6        label 2.1.1

Now I want to find all child by id 2/3/5 etc.. How do I do this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T14:20:34+00:00Added an answer on June 15, 2026 at 2:20 pm

    Suppose table1 is your table name and @input contains the input value

    DECLARE @input INT = 2;
    DECLARE @parent INT = 0;
    DECLARE @name NVARCHAR(200); --same type with name column
    SELECT @parent = parentid, @name = name FROM table1 WHERE id = @input;
    IF @parent = 0
       SELECT * FROM table1 WHERE id <> @input
    ELSE
       SELECT * FROM table1 WHERE name LIKE (@name + '%')
    

    This can be done if the name field has format like in your example.

    For recursive SQL refer this way:

    WITH temptable (id, parentid, name) AS
    (
      SELECT id, parentid, name
      FROM table1 t1
      WHERE t1.id = 1
      UNION ALL
      SELECT t2.id, t2.parentid, t2.name
      FROM table1 t2, temptable t3
      WHERE t2.parentid = t3.id
    )
    SELECT id, parentid, name 
    FROM temptable
    WHERE parentid <> 0
    
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