Question

In header file, I declared the following as a public member variable:

vector< vector<unsigned char> > arImage;

In source code, I define temp

vector<vector<unsigned char> > temp (numImage, vector<unsigned char>(sizeImage));

Now I try to ,

temp.swap(arImage);

But an error occured. (detail errors are omitted because they are not English)

    with
    [
        _Ty=std::vector<unsigned char>
    ]

////////////
Addition,,,,,,,,

I want to swap

    vector<vector<unsigned char> > to vector<vector<unsigned char> >

I’m working with MFC. I can’t find proper method, so I actually take another approach.

In header file,

    vector< vector<unsigned char> > * arImage;

In source code,

    arImage = new vector< vector<unsigned char> > (numImage, vector<unsigned char>(sizeImage));

But this approach is not comfortable.(this approach is no error)

I want to use arImage[i][j].

In this approach, I have to use (*arImage)[i][j]

Answer 1

The thing you are doing wrong here is you are trying to swap vector< unsigned char > with vector of vector< unsigned char > which is not possible.

Vector arImage has items of type unsigned char while temp type is vector<vector<unsigned char> > so temp items are vector<unsigned char>.

So it make sense as can not swap vector<unsigned char> with unsigned char. Similarly you can not swap vector< unsigned char > with vector <vector< unsigned char >>.

I hope it explains everything.