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Home/ Questions/Q 8205575
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T08:17:53+00:00 2026-06-07T08:17:53+00:00

In Java, Class StudentProgress { String Name; String Grade; /* CTOR goes here */

  • 0

In Java,

Class StudentProgress
{
        String Name;
        String Grade;
        /* CTOR goes here */
}

main class
{
     main method()
     {
         StudentProgress arrayofObjects[100000];
     }
}

If the Grades are like D-,C-,B-,A-,A,B,C,D,A+,B+,C+,D+. I need to sort these objects how can I do it efficiently
Thanks in advance

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T08:17:56+00:00Added an answer on June 7, 2026 at 8:17 am

    Your best approach is to make your class implement Comparable. Something like this will work:

    public class StudentProgress implements Comparable<StudentProgress> {
    
        String name;
        String grade;
        char baseGrade;    // Just the letter
        int gradeModifier; // -1 0 or +1 - done to make sorting easier
    
        public StudentProgress( String name, String grade ) {
            this.name = name;
            this.grade = grade;
            // Extract the grade parts for use when comparing
            baseGrade = grade.charAt( 0 );
            gradeModifier = grade.length() == 1 ? 0 : Integer.parseInt( grade.charAt( 1 ) + "1" );
        }
    
        public int compareTo( StudentProgress o ) {
            return baseGrade == o.baseGrade ? gradeModifier - o.gradeModifier : baseGrade - o.baseGrade;
        }
    }
    

    Then to sort, you simply use the Arrays.sort() method:

    StudentProgress[] array = ...;
    Arrays.sort(array);
    

    If you don’t want your class to implement this interface, you can provide a stand-alone Comparator to the sort call

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