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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T07:11:11+00:00 2026-05-23T07:11:11+00:00

in Java, how to parse a date string that contains a letter that does

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in Java, how to parse a date string that contains a letter that does not represent a pattern?

"2007-11-02T14:46:03+01:00"
String date ="2007-11-02T14:46:03+01:00";
String format = "yyyy-MM-ddTHH:mm:ssz";
new SimpleDateFormat(format).parse(date);

Exception in thread "main" java.lang.IllegalArgumentException: Illegal pattern character 'T'
    at java.text.SimpleDateFormat.compile(SimpleDateFormat.java:769)
    at java.text.SimpleDateFormat.initialize(SimpleDateFormat.java:576)
    at java.text.SimpleDateFormat.(SimpleDateFormat.java:501)
    at java.text.SimpleDateFormat.(SimpleDateFormat.java:476)
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  1. Editorial Team
    Editorial Team
    2026-05-23T07:11:12+00:00Added an answer on May 23, 2026 at 7:11 am

    The time you’re trying to parse appears to be in ISO 8601 format. SimpleDateFormat unfortunately doesn’t support all the same timezone specifiers as ISO 8601. If you want to be able to properly handle all the forms specified in the ISO, the best thing to do is use Joda time.

    This example is straight out of the user guide:

    DateTime dt = new DateTime("2004-12-13T21:39:45.618-08:00");
    
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