Question

In Java, I can pass an object straight in parameter

public int foo (Bar bar)
{
    ... call the methods from Bar class
}

So how can I do same thing with PHP. Thanks
This is my code:

class Photo
{
    private $id, $name, $description;
    public function Photo($id, $name, $description)
    {
        $this->id = $id;
        $this->name = $name;
        $this->description = $description;
    }
}
class Photos
{
    private $id = 0;
    private $photos = array();

    private function add(Photo $photo)
    {
        array_push($this->photos, $photo);
    }
    public function addPhoto($name, $description)
    {
        add(new Photo(++$this->id, $name, $description));
    }
}
$photos = new Photos();
$photos->addPhoto('a', 'fsdfasd');
var_dump($photos); // blank

If I change the function add

function add($name, $description)
{
    array_push($this->photos, new Photo(++$this->id, $name, $description));
}

It works pefectly. So What is wrong ?

Answer 1

You do it the exact same way, just with some syntax changes, of course:

public function foo(Bar $bar)
{
    // $bar->method()
}

Keep in mind that you can only type hint for classes and arrays.