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Home/ Questions/Q 8587391
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T22:33:31+00:00 2026-06-11T22:33:31+00:00

In Java, I have such code: boolean contains; for (int i = 0; i

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In Java, I have such code:

boolean contains;
for (int i = 0; i < n; i++) {
    // get the current matrix value
    t = A[i][j];

    // check if it has been already considered
    contains = false;
    for (int z = 0; z < l; z++) {
        if (arrays[z].contains(t)) {
            contains = true; break;
        }
    }
    if (contains) continue;
    ...
}

Is it possible to use label then jump out of the inner loop and do continue without a boolean variable contains?

I need to do break-continue and not break from all loops.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T22:33:32+00:00Added an answer on June 11, 2026 at 10:33 pm
    outerLoop:
    for (int i = 0; i < n; i++) {
        // get the current matrix value
        t = A[[i]][j];
        // check if it has been already considered
        for (int z = 0; z < l; z++) {
            if (arrays[z].contains(t)) {
                continue outerLoop;
            }
        }
    }
    

    Oracle’s documentation on labelled branching

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