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Asked: 2026-05-15T14:30:11+00:00

In Java I run: System.out.println(Math.log(249.0/251.0)); Output: -0.008000042667076265 In C# I run: <- fixed Math.Log

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In Java I run:

System.out.println(Math.log(249.0/251.0));

Output: -0.008000042667076265

In C# I run: <- fixed

Math.Log (x/y); \\where x, y are almost assuredly 249.0 and 251.0 respectively

Output: -0.175281838 (printed out later in the program)

Google claims:

Log(249.0/251.0)

Output: -0.00347437439

And MacOS claims about the same thing (the first difference between google and Snow Leopard is at about 10^-8, which is negligible.

Is there any reason that these results should all vary so widely or am I missing something very obvious? (I did check that java and C# both use base e). Even mildly different values of e don’t seem to account for such a big difference. Any suggestions?

EDIT:

Verifying on Wolfram Alpha seems to suggest that Java is right (or that Wolfram Alpha uses Java Math for logarithms…) and that my C# program doesn’t have the right input, but I am disinclined to believe this because taking (e^(google result) – 249/251) gives me an error of 0.0044 which is pretty big in my opinion, suggesting that there is a different problem at hand…

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1 Answer

  1. Editorial Team

    You’re looking at logarithms with different bases:

    • Java’s System.out.println(Math.log(249.0/251.0)); is a natural log (base e)
    • C#’s Math.Log (x,y); gives the log of x with base specified by y
    • Google’s Log(249.0/251.0) gives the log base 10

    Though I don’t get the result you do from C# (Math.Log( 249.0, 251.0) == 0.998552147171426).

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