Question

In Java, I use log4J that is a logging framework. In Log4j you can do something like this:

if (log.isDebug()) {   // do some expensive operation that should only be displayed if DEBUG is turned on } 

Reading some Symfony examples, I am unable to find a way to determine if DEBUG logging is activated in the current class context. Is there a way to do this?

if (--need something here--) {   $this->logMessage('Expensive operation return value: '.expensiveFunction(), 'debug'); } 

Answer 1

something like

$this->getLogger()->getLogLevel() == sfLogger::DEBUG 

should do.