Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 3484836
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 18, 20262026-05-18T10:50:06+00:00 2026-05-18T10:50:06+00:00

In Java, I’m trying to retrieve a HashMap<String, Object> that has the Object which

  • 0

In Java, I’m trying to retrieve a HashMap<String, Object> that has the Object which is: HashMap<String, Object>.

I implemented a recursive function that returns either the HashMap<String, Object> found with the given key, or null if the key wasn’t found.

Here is the function:

public static HashMap<String, Object> getHashMap(HashMap<String, 
                                      Object> map, String key)
{
    for (Map.Entry<String, Object> entry : map.entrySet()) {
     if (entry.getValue().getClass().getName() == "java.util.HashMap") {
         if (entry.getKey() == key) 
          return (HashMap<String, Object>) entry.getValue();
         return getHashMap((HashMap<String, Object>) entry.getValue(), key);
     }
    }
    return null;
}

It only works for the first item. How do I traverse a Hashmap of HashMaps? What is a better approach?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-18T10:50:06+00:00Added an answer on May 18, 2026 at 10:50 am

    Instead of returning the value immediately here:

    return getHashMap((HashMap<String, Object>) entry.getValue(), key);
    

    you want to first check if it is not null, and return it only then. Otherwise you should just continue searching:

    HashMap<String, Object> result = getHashMap((HashMap<String, Object>) entry.getValue(), key);
    if (result != null)
      return result;
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Java has a Properties class that is nice for saving basic configuration information, e.g.
Java Wrapper classes are supposed to be immutable. This means that once an object
java.util.date = org.apache.commons.lang.time.DateUtils.parseDate(value, new String[] { mm/dd/yyyy }); If you give an invalid date
Java IO implementation of unix/linux "tail -f" has a similar problem; but the solution
Java Socket Server I have a Java process that is creating a listener on
Java netty can only take X number of request per second? With the selector
Java is the language, the JRE is the runtime environment, and the JDK are
Java EE 6, NetBeans 6.9.1. Part of my project is a SOAPy web service.
Java is most important language for mobile devices as it allows the same binary/byte
Java annotation processing (since Java 6) is a very good concept, because it allows

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.