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Editorial Team
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Asked: 2026-06-14T09:50:34+00:00

In Java, it won’t allow me to use a long for something like this:

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In Java, it won’t allow me to use a long for something like this:

long size = 0xFFFFFFFF; //2^32-1

byte [] data = new byte[size];

And an int can only go as high as 0x7FFFFFFF (2^31-1). Is it possible to declare a byte array of this size?

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1 Answer

  1. Editorial Team

    Answer is NO as this is the max possible initialization:

        int size = Integer.MAX_VALUE;
    byte [] data = new byte[size];
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