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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T04:45:17+00:00 2026-05-27T04:45:17+00:00

In Java, the instanceof operator will only return false if comparing null . If

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In Java, the instanceof operator will only return false if comparing null. If you test a reference variable that isn’t of the required type, the program fails to compile.
Does this operator effectively only test if a reference is null or not? Or is there another use I’m not thinking of?

If not, why not call it isNull or something more descriptive?

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  1. Editorial Team
    Editorial Team
    2026-05-27T04:45:18+00:00Added an answer on May 27, 2026 at 4:45 am

    It fails to compile if the comparison can never be true. For example:

    "string" instanceof Number
    

    This will not compile because the compiler knows that a string can never be a number. The operator does exactly what one would expect it to do: it tests if the operand is an instance of the specified type.

    Returning false when testing a null reference is meant to make the code simpler and more readable. It prevents you from needing to do this:

    if (obj != null && obj instanceof Number) {
        ...
    }
    

    Read this to learn about the operator: http://java.sun.com/docs/books/jls/third_edition/html/expressions.html#15.20.2

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