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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T17:28:01+00:00 2026-05-11T17:28:01+00:00

In Java you can define generic class that accepts only types that extend a

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In Java you can define generic class that accepts only types that extend a class of your choice:

public class ObservableList<T extends List> {
    /* ... */
}

This is done using extends keyword.

Is there some simple equivalent to this keyword in C++?

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  1. Editorial Team
    Editorial Team
    2026-05-11T17:28:02+00:00Added an answer on May 11, 2026 at 5:28 pm

    I suggest using Boost’s static assert feature in concert with is_base_of from the Boost Type Traits library:

    template<typename T>
    class ObservableList {
        BOOST_STATIC_ASSERT((is_base_of<List, T>::value)); //Yes, the double parentheses are needed, otherwise the comma will be seen as macro argument separator
        ...
    };
    

    In some other, simpler cases, you can simply forward-declare a global template, but only define (explicitly or partially specialise) it for the valid types:

    template<typename T> class my_template;     // Declare, but don't define
    
    // int is a valid type
    template<> class my_template<int> {
        ...
    };
    
    // All pointer types are valid
    template<typename T> class my_template<T*> {
        ...
    };
    
    // All other types are invalid, and will cause linker error messages.
    

    [Minor EDIT 6/12/2013: Using a declared-but-not-defined template will result in linker, not compiler, error messages.]

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