Question

In JavaScript, I have the following:

function replaceURLWithHTMLLinks(text) {
    var exp = /(\b(https?|ftp|file):\/\/[-A-Z0-9+&@#\/%?=~_|!:,.;]*[-A-Z0-9+&@#\/%=~_|])/ig;
    return text.replace(exp,"<a href='$1'>$1</a>"); 
}

It replaces all of the URLs in the input string with a version of the URL that has an anchor tag wrapped around it to turn it into a link. I’m trying to duplicate this functionality in Java with the following function:

private String replaceURLWithHTMLLinks(String text) {
    String pattern = "/(\\b(https?|ftp|file):\\/\\/[-A-Z0-9+&@#\\/%?=~_|!:,.;]*[-A-Z0-9+&@#\\/%=~_|])/i";
    return text.replaceAll(pattern, "<a href=\"$1\">$1</a>");
}

However, while it works fine in JavaScript it doesn’t find any matches in Java, even for the same input string. Do I need to change something in the pattern, or what’s going on?

Answer 1

You need to get rid of the slashes around the expression and the i at the end for the Java example. You can specify the i flag separately. So JavaScript’s /blarg/i would be turned into "(?i)blarg".

Your code would become something like:

private String replaceURLWithHTMLLinks(String text) {
  String pattern = "(?i)(\\b(https?|ftp|file):\\/\\/[-A-Z0-9+&@#\\/%?=~_|!:,.;]*[-A-Z0-9+&@#\\/%=~_|])";
  return text.replaceAll(pattern, "<a href=\"$1\">$1</a>");
}