Question

In javascript:

"Id".localeCompare("id")

will report that “id” is bigger. I want to do ordinal (not locale) compare such that “Id” is bigger. This is similar to String.CompareOrdinal in C#. How can I do it?

Answer 1

As Raymond noted (and explained) in a comment, an “ordinal” non-locale aware compare is as simple as using the various equality operators on strings (just make sure both operands are strings):

"a" > "b" // false 
"b" > "a" // true

To get a little fancy (or don’t muck with [[prototype]], the function is the same):

String.prototype.compare = function (a, b) {
    return ((a == b ? 0)
        ? (a > b : 1)
        : -1)
}

Then:

"a".compare("b") // -1

Happy coding.