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Home/ Questions/Q 8072915
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T14:10:34+00:00 2026-06-05T14:10:34+00:00

In knockout.js 2.1.0, in a template using the foreach binding, you can access the

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In knockout.js 2.1.0, in a template using the foreach binding, you can access the current item’s index though the $index() function. In a nested foreach binding, is there any way to access the index of the $parent from a template?

Say I have a data structure like this:

var application = {
  topModel: [
    {
      {subModel: [{'foo':'foo'}, { 'bar':'bar'}]}, // this has top:0 and sub:0
      {subModel: [{'foo2':'foo2'}, { 'bar2':'bar2'}]} // this has top:0 and sub:1
    },
    {
      {subModel: [{'foo':'foo'}, { 'bar':'bar'}]} // this is top:1 sub:0
    },
    {
      {subModel: [{'foo':'foo'}, { 'bar':'bar'}]} // this is top:2 sub:0
      {subModel: [{'foo':'foo'}, { 'bar':'bar'}]} // this is top:2 sub:1
    },
    ...
    ]};

With this, I want to print the path to each model, using indices:
[topModel-index subModel-index], so that the output will be something like:

[0 0]
[0 1]
[1 0]
[2 0]
[2 1]
...

I have bound the models using foreach, but I can’t figure out how to access the topModel’s index in the context of the subModel. The following example shows an approach I have tried, but it doesn’t work, as I can’t figure out how to access the index of the $parent referrer.

<!--ko foreach: topModel -->
<!--ko foreach: subModel -->
  [<span data-bind="text: $parent.index()"></span>
  <span data-bind="text: $index()"></span>]
<!--/ko-->
<!--/ko-->

Should print out: 0 1, 0 2, 1 0, 1 1, 1 2, 2 0, 2 1, …

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T14:10:35+00:00Added an answer on June 5, 2026 at 2:10 pm

    to access the index of the parent object use

    $parentContext.$index()
    

    rather than

    $parent.index()
    
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