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in Linux kernel source code, I find below code:
h++;
pending >>= 1;
It is part of __do_softirq(void). But what does “>>=” mean? Why isn’t it “>>” as I remember?
Thanks!
It simply does
In short it divides by 2 an unsigned int.
That’s the same construct than
+=,/=, etc.It’s not just
pending >>1as you remember because that wouldn’t store the result of the shift operation in the variable.