Question

In most examples I found on the Internet , I see something like this :

ajaxRequest.onreadystatechange = function() {   
    if(ajaxRequest.readyState == 4) {
        document.myForm.time.value = ajaxRequest.responseText;
    }
}

ajaxRequest.open("GET", "serverTime.php", true);
ajaxRequest.send(null);

How is it possible and how does this code work , when the “change state”
property is checked
BEFORE
the open and send commands are executed ?
I know it works…but how does the flow return back to “check the state
status” after the “open” and “send” are executed.

I would appreciate any help

Many thanks in advance 🙂

Answer 1

Because onreadystatechange is an event, and that code won’t get invoked until the ready state changes, which will occur at some point in the future when the request is complete.