Question

In my Android app, I have a dialog with a few options, one of which should result in the current dialog being displayed again.

It’s like this:

protected Dialog onCreateDialog(int id) {
    AlertDialog.Builder builder = new AlertDialog.Builder(this);
    if (id == 0) {
        builder.setMessage("Message 0")
               .setPositiveButton("Show Message 0 Again", new DialogInterface.OnClickListener() {
                   public void onClick(DialogInterface dialog, int id) {
                       showDialog(0);
                   }
               })
               .setNegativeButton("Show Message 1", new DialogInterface.OnClickListener() {
                   public void onClick(DialogInterface dialog, int id) {
                       showDialog(1);
                   }
               });
    } else {
        builder.setMessage("Message 1")
               .setPositiveButton("Dismiss", new DialogInterface.OnClickListener() {
                   public void onClick(DialogInterface dialog, int id) {
                       // nothing
                   }
               });
    }
    AlertDialog dialog = builder.create();
    return dialog;
}

However, when I click on the “Show Message 0 Again” button, the dialog is dismissed and does not appear again. The “Show Message 1” button works fine.

I would prefer the dialog to actually be dismissed and then opened again, rather than simply having the “Show Message 0 Again” button just not do anything and not cause the dialog to be dismissed, if that’s possible.

Answer 1

Here is the discussion : Dialog.show() vs. Activity.showDialog()

Please Have a look on that…

Hopes it Helps. 🙂