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Home/ Questions/Q 7871491
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T01:55:19+00:00 2026-06-03T01:55:19+00:00

in my Android app I need to run an HTTP web server. Initial bringup

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in my Android app I need to run an HTTP web server. Initial bringup seems ok – I can receive requests and process the URI string when I’m using a Browser to navigate to a page on that server (I see GET request with full URI with all parameters).
However, if I’m using a form that submits request to a server:

<FORM action="http://192.168.1.107:8080/testaction" method="post">
    <INPUT type="text" name="textfield" /><BR>
    <INPUT type="submit" value="Send"/>
 </FORM>

I only get the action in the URI (like “/testaction”). I cannot figure out how to get the actual data of the POST request.

Here is the part that handles the request in java code:

public class HomePageHandler implements HttpRequestHandler {
...
        @Override
        public void handle(HttpRequest request, HttpResponse response, HttpContext httpContext) throws HttpException, IOException {

                String uriString = request.getRequestLine().getUri();
                Uri uri = Uri.parse(uriString);
...
}

I realize I could be doing something wrong in java and/or HTML form itself. Please advise on both.

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  1. Editorial Team
    Editorial Team
    2026-06-03T01:55:20+00:00Added an answer on June 3, 2026 at 1:55 am

    To get the POST body, you can do this:

    if (request instanceof HttpEntityEnclosingRequest) { //test if request is a POST
        HttpEntity entity = ((HttpEntityEnclosingRequest) request).getEntity();
        String body = EntityUtils.toString(entity); //here you have the POST body
    }
    
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