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Home/ Questions/Q 7544669
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T08:43:55+00:00 2026-05-30T08:43:55+00:00

In my Android project I have a regular expression and a string, in which

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In my Android project I have a regular expression and a string, in which I should have the matched expression. The problem is, I’ve only found a matches() method, which returns boolean. Is there something, which returns only the matched string (for instance, if my string is “go to the shop at 12pm”, I want to check if there is a time in this string (in this example – “12pm”), if it is – return it) ?
Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-05-30T08:43:57+00:00Added an answer on May 30, 2026 at 8:43 am

    you should get capturing group you need. Read this. You’ll find answer to your question.
    Here is a simple example for you. I think you’ll understand it.

    Pattern p = Pattern.compile(".*?(\\d{2}(am|pm)).*");
    Matcher m = p.matcher("go to the shop at 12pm");
    if(m.matches())
       return m.group(1);
    

    This will return 12pm
    Actually you can get what you want with better way.

    Pattern p = Pattern.compile("\\d{2}(am|pm)");
    Matcher m = p.matcher("go to the shop at 12pm");
    if(m.find())
       return m.group(0);    //or you can write return m.group(); result will be the same.
    
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