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Home/ Questions/Q 9320889
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Editorial Team
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Editorial Team
Asked: June 19, 20262026-06-19T03:44:48+00:00 2026-06-19T03:44:48+00:00

in my app I have this code to register to the GCM service: Server.java

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in my app I have this code to register to the GCM service:

Server.java

protected void registerToGcm() {
    GCMRegistrar.checkDevice(mContext);
    GCMRegistrar.checkManifest(mContext);
    String regId = GCMRegistrar.getRegistrationId(mContext);
    if ("".equals(regId)) {
        GCMRegistrar.register(mContext, GCMIntentService.SENDER_ID);
    } else {
        registerToServer(regId);
    }
}

GCMIntentService.Java

public static final String SENDER_ID = "1111111111";
@Override
protected void onRegistered(Context context, String regId) {
    Log.d(TAG, "Registered to GCM with regId: " + regId);
    Server.registerToServer(regId);
}

when I run this code, I see in the server that my device is registering twice with 2 different regIds, and when the server sends a push, the device receives 2 messages.

is this a normal thing? is there a way to ensure only one regId?

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  1. Editorial Team
    Editorial Team
    2026-06-19T03:44:49+00:00Added an answer on June 19, 2026 at 3:44 am

    What do you need to check when you want to register is

    GCMRegistrar.checkDevice(getApplicationContext());
    GCMRegistrar.checkManifest(getApplicationContext());
    
    deviceToken = GCMRegistrar.getRegistrationId(getApplicationContext());
    
    if (printLog == true)
        Log.i("Home", "Registration id =====  " + deviceToken);
    if (deviceToken.equals("")) {
        GCMRegistrar.register(getApplicationContext(), SENDER_ID);
    } else {
        if (printLog == true)
            Log.v("Home", "Device Already registered");
    }
    
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