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Home/ Questions/Q 5843597
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T12:10:35+00:00 2026-05-22T12:10:35+00:00

In my AppDelegate I have a reference to an NSObject like this: @interface MyAppDelegate

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In my AppDelegate I have a reference to an NSObject like this:

@interface MyAppDelegate : NSObject <UIApplicationDelegate>
{
    MyObjectManager * myObjectManager;
}

@property (nonatomic, retain) IBOutlet UIWindow *window;
@property (nonatomic, retain) IBOutlet UINavigationController *navigationController;

@property (nonatomic, retain) MyObjectManager * myObjectManager;

I want to access this from my UIViewController, so I do this:

MyAppDelegate * appDelegate = (MyAppDelegate *)[[UIApplication sharedApplication] delegate];
MyObjectManager * myObjectManager = appDelegate.myObjectManager;
maMyArray = [[NSMutableArray alloc] init];

[[appDelegate myObjectManager] findMyStuff:5 foundArray:maMyArray];
//[myObjectManager findMyStuff:5 foundArray:maMyArray];

However, I think I am not understanding the syntax in Objective C correctly because I throw an exception, EXC_BAD_ACCESS. When I look at the values, they seem correct.

Can someone please explain what I am doing wrong?

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-22T12:10:36+00:00Added an answer on May 22, 2026 at 12:10 pm

    You have to initialize myObjectManager somwhere:

    myObjectManager = [[MyObjectManager alloc] init];
    

    The best place is probably in the - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions method.

    Don’t forget to release it in the dealloc.

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