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Home/ Questions/Q 9115623
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T04:28:35+00:00 2026-06-17T04:28:35+00:00

In my application I call setContentView( layout1.xml ); , I want to access an

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In my application I call setContentView( layout1.xml );, I want to access an element within a DIFFERENT layout file, lets call it layout2.xml.

I have tried

view1 = (View) findViewById( R.layout.layout2 ); 

and also added an id to the layout and tried

view1 = (View) findViewById( r.id.layout2 ); 

Neither of these work. They compile just fine but when I run it, as soon as i try to call something like

button1 = view1.findViewById( R.id.button1 );

I get a null pointer exception.

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  1. Editorial Team
    Editorial Team
    2026-06-17T04:28:36+00:00Added an answer on June 17, 2026 at 4:28 am

    You need to use a layout inflater to get your second layout like so:

     View view = LayoutInflater.from(getBaseContext()).inflate(R.layout.layout2, null);
    

    And then reference your button from that layout:

    Button button1 = view.findViewById( R.id.button1 );
    
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