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Home/ Questions/Q 4059152
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T15:10:17+00:00 2026-05-20T15:10:17+00:00

In my application, I have many IF statements that could be optimizing, but for

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In my application, I have many IF statements that could be optimizing, but for the life of me can’t work out a good possible solution without errors.

My current code:

    if (User_XP > -1){User_level.setText("1");Minimum_Level= Level1; Maximum_level = Level2;}
    if (User_XP > Level1){User_level.setText("1");Minimum_Level= Level1; Maximum_level = Level2;}
    if (User_XP > Level2){User_level.setText("2");Minimum_Level = Level2; Maximum_level = Level3;}
    if (User_XP > Level3){User_level.setText("3");Minimum_Level = Level3; Maximum_level = Level4;}
    if (User_XP > Level4){User_level.setText("4");Minimum_Level = Level4; Maximum_level = Level5;}
    if (User_XP > Level5){User_level.setText("5");Minimum_Level = Level5; Maximum_level = Level6;}
    if (User_XP > Level6){User_level.setText("6");Minimum_Level = Level6; Maximum_level = Level6;}
    if (User_XP > Level7){User_level.setText("7");Minimum_Level = Level7; Maximum_level = Level6;}
    if (User_XP > Level8){User_level.setText("8");Minimum_Level = Level8; Maximum_level = Level6;}
    if (User_XP > Level9){User_level.setText("9");Minimum_Level = Level9; Maximum_level = Level6;}

The idea of it is to work out a users level from a game, and from that create a percentage. But this area of coding is really not efficient as it can create multiple errors, anyone got any tips on a possible solution?
Please ask if more information is needed.

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  1. Editorial Team
    Editorial Team
    2026-05-20T15:10:17+00:00Added an answer on May 20, 2026 at 3:10 pm

    Perhaps store your level experience requirements in an array and use a loop.

    int[] levels = new int[] { -1, Level1, Level2, Level3 };
    
    int level;
    for (level = 0; level < levels.length && userXp < levels[level]; level++) { }
    int minLevel = levels[level];
    int maxLevel = levels[level + 1];
    userLevelText.setText(Integer.toString(minLevel));
    
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