In my application, I have three layers of modal view controllers.
1) So my rootViewController is a tabbar.
2) On applicationDidFinishLaunching I am presenting a viewController, say viewController A modally above tabbar.
3) On click of a button in ‘viewController A’, I present another viewController B modally.
4) And a button action on viewController B presents navigationController modally with its rootViewController as viewController C.
5) Finally from viewController C, I want to go back to viewController A.
I tried using
[[[self parentViewController] parentViewController]dismissModalViewControllerAnimated:YES];
in viewController C, but it reverts me back to viewController B instead of viewController A.
How can I revert back to viewController A.
Any help would be appreciated.
You’ve got a complex VC stack. You could as one poster suggested implement a custom dismissView method, but that would be fragile: if you reuse this view, or move it in your app, it will cease functioning, because it relies too much on specific knowledge of how other VCs have configured their state.
You could configure a delegation chain. This would be the standard way to manipulate views: the presenting VC is also responsible for removing anything it presents.
To do so, build a protocol implemented by B, and initialize C with a reference to B. Similarly, initialize B with a reference to A (with potentially the same protocol, depending on any other communication that needs to be passed between them.)
Then when the button is clicked on C, it calls B’s delegate method. B unwinds C as appropriate, and calls A’s delegate method. A unwinds B as appropriate.
This has the advantage of keeping VC knowledge encapsulated: A knows how it presented B, so it knows how to unpresent it, and B knows how it presented C, and knows how to un-present it. In no case does one VC need to make assumptions about how it was presented by another.