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Editorial Team
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Asked: 2026-05-26T17:45:19+00:00

In my application, I have three tabs in the Action Bar. Tab A :

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In my application, I have three tabs in the Action Bar.

Tab A : contains 2 fragments
Tab B : contains a WebViewFragment
Tab C : contains a WebViewFragment

Now, I use a global layout containing a LinearLayout.
I inflate the right layout in the LinearLayout according to the tab. But when I switch between B -> A, I get this error :

Caused by: java.lang.IllegalArgumentException: Binary XML file line #8: Duplicate id 0x7f0a0002, tag null, or parent id 0xffffffff with another fragment for com.myapp.CategoriesFragment

What is the best solution to handle this ?

I have tried to removeAllViews / reAdd the layout, but I get this Exception :

java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first.

I think I haven’t choose the right solution.
Thanks for your answers

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1 Answer

  1. Editorial Team

    You can choose an inner container to hold the fragments
    Refer to the sample layout below

    <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical" android:layout_width="fill_parent"
android:layout_height="fill_parent">

    <LinearLayout android:id="@+id/fragment_container"    
          xmlns:android="http://schemas.android.com/apk/res/android"
      android:orientation="vertical" android:layout_width="fill_parent"
      android:layout_height="wrap_content"/>
</LinearLayout>
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