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Home/ Questions/Q 6732015
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T10:35:54+00:00 2026-05-26T10:35:54+00:00

In my bash test has an attitude to exit with status 0 : $

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In my bash test has an attitude to exit with status 0:

$ test -n && echo true || echo false
-> true

while

$ test -n "" && echo true || echo false
-> false

It means when it doesn’t receive any argument at all, it assumes nonzero.

The case -z works properly instead:

$ test -z && echo true || echo false
-> true
$ test -z "" && echo true || echo false
-> true

Is this the expected behavior?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T10:35:55+00:00Added an answer on May 26, 2026 at 10:35 am

    Basically, you are asking test whether the string “-z” is nonempty. It is, so it tells you true. The actual algorithm test uses is:

    • 0 arguments:

      Exit false (1).

    • 1 argument:

      Exit true (0) if $1 is not null; otherwise, exit false.

    • 2 arguments:

      If $1 is ‘!’, exit true if $2 is null, false if $2 is not null.

      If $1 is a unary primary, exit true if the unary test is true, false
      if the unary test is false.

      Otherwise, produce unspecified results.

    …

    Quoted from the POSIX test command specification.

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