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Editorial Team
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Asked: 2026-05-24T02:17:24+00:00

In my BAT file I would like to have something like: set javaVersion=… if

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In my BAT file I would like to have something like:

set javaVersion=...

if %javaVersion% equ 32 (
  echo "do 32 Java routine"
) else (
  echo "do non-32 Java routine"
)

On a 64bit machine, with JRE 64bit installed, in the registry under HKEY_LOCAL_MACHINE\SOFTWARE\JavaSoft\Java Runtime Environment and HKEY_LOCAL_MACHINE\SOFTWARE\JavaSoft\Java Runtime Environment\1.6 I see almost the same values as on a 32bit machine with JRE 32bit installed: 

HKEY_LOCAL_MACHINE\SOFTWARE\JavaSoft\Java Runtime Environment
    CurrentVersion:       1.6
    Java6FamilyVersion:   1.6.0_26

HKEY_LOCAL_MACHINE\SOFTWARE\JavaSoft\Java Runtime Environment\1.6
    JavaHome:             C:\Program Files\Java\jre6
    MicroVersion:         0
    RuntimeLib:           C:\Program Files\Java\jre6\bin\client\jvm.dll

Therefore, I could check if it is 64bit Java by checking if PROGRAMFILES(X86) is defined and if JavaHome points to location which starts with C:\Program Files\.

But is there a better option?

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1 Answer

  1. Editorial Team

    You could capture the output of java -version – it’s in there.
    Here’s the output on my mac:

    java version "1.6.0_26"
Java(TM) SE Runtime Environment (build 1.6.0_26-b03-384-10M3425)
Java HotSpot(TM) 64-Bit Server VM (build 20.1-b02-384, mixed mode)

    You should find either “64-Bit” or “32-Bit” in the output.

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