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Home/ Questions/Q 7004345
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T21:11:15+00:00 2026-05-27T21:11:15+00:00

in my c application I have this typedef: typedef double mat[2][2]; this is my

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in my c application I have this typedef:

typedef double mat[2][2];

this is my declaration of function:

aaa(mat bbb, mat ccc, mat * ddd)

in my code I want to compute the sum of each member in math and write the result in ddd.
I did it over loops and this is the main line:

*ddd[i][j] = bbb[i][j] + ccc[i][j];

but I’m getting wrong result in ddd.
when I remove the pointer from ddd, I get the right result, but since I want to return it to the user by pointer I want your help.

what is wrong in my code?

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  1. Editorial Team
    Editorial Team
    2026-05-27T21:11:16+00:00Added an answer on May 27, 2026 at 9:11 pm

    You’re writing at the wrong address. It should be:

    (*ddd)[i][j] = bbb[i][j] + ccc[i][j];
    

    or simply change the prototype to

    aaa(mat bbb, mat ccc, mat ddd)
    

    since arrays decay to pointers anyway. ddd will be a copy, but the address it points to will be the same as the original.

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