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Home/ Questions/Q 7525759
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T03:38:29+00:00 2026-05-30T03:38:29+00:00

In my C++ code I’m keeping a pointer to an object which should be

  • 0

In my C++ code I’m keeping a pointer to an object
which should be created lazily, i.e., created only upon request.
I have following code, which is clearly not thread-safe.

LAZY* get_lazy()
{
    if (0 == _lazy)
        _lazy = create_lazy();
    return _lazy;
}

I wonder what kind of synchronization should I use here?
I know Boost.thread provides supports for one-time initialization.
But I’m hoping that there is a simple solution using TBB + C++ only.
I should also note that…

  • I cannot create _lazy as a static object (I actually want to keep an unbounded array of such lazily created objects)
  • Such LAZY objects cannot be over-allocated (creation is very expensive)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T03:38:31+00:00Added an answer on May 30, 2026 at 3:38 am

    You need a local mutex (tbb::mutex), to be sure you create your lazy object only once.

    #include <tbb/mutex.h>
    
    tbb::atomic<LAZY*> _lazy;
    tbb::mutex myMutex;
    
    LAZY* GetLazy()
    {
      if (0 == _lazy)
      {
        myMutex.lock();
        if (0 == _lazy)
            _lazy = create_lazy();
        myMutex.unlock();
      }
      return _lazy;
    }
    
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