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Home/ Questions/Q 8552671
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T14:28:32+00:00 2026-06-11T14:28:32+00:00

In my class, I have a member variable std::vector<node*> children Does the following class

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In my class, I have a member variable std::vector<node*> children

Does the following class member function create a memory leak?

//adds a child node
{
    node* child = new node("blah","blah","blah");
    child->Set_Parent(this);
    children.push_back(child);  //<- Is this ok?
}

The vector makes a copy of the pointer and I have two pointers to the same memory,
and then the original pointer goes out of scope, right?

This may be simple and obvious, but I would just like to confirm my assumption.
thanks

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  1. Editorial Team
    Editorial Team
    2026-06-11T14:28:33+00:00Added an answer on June 11, 2026 at 2:28 pm

    It’s not a leak … yet. However, if the vector goes out of scope, or you erase, pop_back or do something else that removes elements from the vector, without first deleteing the element that you’re removing you’ll have a leak on your hands.

    The right way to do this is to change from using a vector<node *> to vector<unique_ptr<node>>. Your code will change to

    //adds a child node
    {
        node* child = new node("blah","blah","blah");
        child->Set_Parent(this);
        children.push_back(std::unique_ptr<node>(child));
    }
    

    Or use boost::ptr_vector<node> if you can use Boost.

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