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Home/ Questions/Q 7780331
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T18:51:41+00:00 2026-06-01T18:51:41+00:00

In my class Tabla I have a public pointer to method: public: int (Tabla

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In my class Tabla I have a public pointer to method:

public:
    int (Tabla :: *punterofunc)(int,int);

In main I point it to a class method:

tablita.punterofunc = &Tabla :: in_lineal;

But this call doesn’t work!

 tablita->punterofunc(num,0);
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  1. Editorial Team
    Editorial Team
    2026-06-01T18:51:43+00:00Added an answer on June 1, 2026 at 6:51 pm

    I think you’re looking for this tasty syntax:

    ((tablita).*(tablita.punterofunc))(num,0);
    

    tablita.punterofunc is a member function pointer. The general syntax for calling a pointer-to-member-function p on an object o is:

    ((o).*(p))(args...);
    

    Just apply that to your code. (Some of the parens might not be necessary in all cases (not sure), but if you stick with that, it should work all the time.)

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