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Home/ Questions/Q 6992953
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T19:42:06+00:00 2026-05-27T19:42:06+00:00

In my code I am checking whether variables exist. But it is not turning

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In my code I am checking whether variables exist. But it is not turning out the way I expect it.

This is what I’m trying to do:

  1. Retrieve $result from database.
  2. Execute a block of code only if a result has been extracted (otherwise do nothing/skip over/move forward).

I used if(isset($result)) but it doesn’t seem to be working, looks like the if is being executed, even though it shouldn’t when there is no data in $result. (but with problems because there is no actual $result variable to use in this block)

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  1. Editorial Team
    Editorial Team
    2026-05-27T19:42:07+00:00Added an answer on May 27, 2026 at 7:42 pm

    To check if there is any data extracted, use this :

    $connect = mysql_connect("127.0.0.1",$sql_username,$sql_password);
    $data = mysql_query($sql_query,$connect);
    $result = mysql_fetch_array($data);
    if($result) { ... }
    
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