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Home/ Questions/Q 154375
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Asked: May 11, 20262026-05-11T09:58:04+00:00 2026-05-11T09:58:04+00:00

In my code I have to do a lot of distance calculation between pairs

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In my code I have to do a lot of distance calculation between pairs of lat/long values.

the code looks like this:

double result = Math.Acos(Math.Sin(lat2rad) * Math.Sin(lat1rad)  + Math.Cos(lat2rad) * Math.Cos(lat1rad) * Math.Cos(lon2rad - lon1rad)); 

(lat2rad e.g. is latitude converted to radians).

I have identified this function as the performance bottleneck of my application. Is there any way to improve this?

(I cannot use look-up tables since the coordinates are varying). I have also looked at this question where a lookup scheme like a grid is suggested, which might be a possibility.

Thanks for your time! 😉

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  1. 2026-05-11T09:58:05+00:00Added an answer on May 11, 2026 at 9:58 am

    If your goal is to rank (compare) distances, then approximations (sin and cos table lookups) could drastically reduce your amount of computations required (implement quick reject.)

    Your goal is to only proceed with the actual trigonometric computation if the difference between the approximated distances (to be ranked or compared) falls below a certain threshold.

    E.g. using lookup tables with 1000 samples (i.e. sin and cos sampled every 2*pi/1000), the lookup uncertainty is at most 0.006284. Using uncertainty calculation for the parameter to ACos, the cumulated uncertainty, also be the threshold uncertainty, will be at most 0.018731.

    So, if evaluating Math.Sin(lat2rad) * Math.Sin(lat1rad) + Math.Cos(lat2rad) * Math.Cos(lat1rad) * Math.Cos(lon2rad - lon1rad) using sin and cos lookup tables for two coordinate-set pairs (distances) yields a certain ranking (one distance appears greater than the other based on the approximation), and the difference’s modulus is greater than the threshold above, then the approximation is valid. Otherwise proceed with the actual trigonometric calculation.

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