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Home/ Questions/Q 7019873
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T23:14:32+00:00 2026-05-27T23:14:32+00:00

In my code, I have used : Application.launch(MyDesign.getClass(), null); to run a UI of

  • 0

In my code, I have used :

Application.launch(MyDesign.getClass(), null);

to run a UI of MyDesign from a seperate class.
When it calls launch(), it executes the constructor of MyDesign class. I have created a MyDesign object earlier and initialized its attributes. So I got a new object after calling launch(). I need to stop the calling its constructor when I call

Application.launch().

Your feed back is highly appreciated. Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-27T23:14:33+00:00Added an answer on May 27, 2026 at 11:14 pm

    Unfortunately you can’t directly run already created Application through Application.launch().

    You can use next stub application and launch it instead:

    public class Runner extends Application {
    
        @Override
       public void start(Stage stage) throws Exception {
           myDesignInstance.start(stage);
       }
    }
    
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