Question

In my college days I remember a php code that handles errors like this..

$rs = $mymodel->find("usr=:usr",array("usr"=>"mahan")) on error echo $mymodel->geterror();

but i know the code above is wrong…

It’s an error handling code I could not remember anymore..

maybe you would suggest something like this

/**First code suggestion**/
    if(!mymodel->find("usr=:usr",array("usr"=>"mahan"))){
        $rs = mymodel->find("usr=:usr",array(":usr"=>"mahan"));
    }

or like this

/**Second code suggestion**/
    try{
       $rs = mymodel->find("usr=:usr",array("usr"=>"mahan"));
    }
    catch(Exception $e){
      dump($e);
    }

My problem is I don’t want to repeat the same operation just to test it if it will have errors(shown on the first code suggestion).

And the second code suggestion doesn’t work.

the error handling I shown on very foremost of my question is wrong but I think it would solve my problem(I just don’t remember the right one)… if not tell me your suggestions.

I’m using Yii Framework

Answer 1

Don’t understand where you hit the road block because you can still assign to a variable:

if (! $rs = $mymodel->find("usr=:usr",array("usr"=>"mahan")))
{
   # failed.
}

So there is no need to execute the same function again.