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Home/ Questions/Q 830297
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T04:01:19+00:00 2026-05-15T04:01:19+00:00

In my database, I have a keywords field that stores a comma-delimited list of

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In my database, I have a keywords field that stores a comma-delimited list of keywords.

For example, a Shrek doll might have the following keywords:

ogre, green, plush, hero, boys' toys

A “Beanie Baby” doll ( that happens to be an ogre ) might have:

beanie baby, kids toys, beanbag toys, soft, infant, ogre

(That’s a completely contrived example.)

What I’d like to do is if the consumer searches for “ogre” I’d like the “Shrek” doll to come up higher in the search results.

My content administrator feels that if the keyword is earlier in the list, it should get a higher ranking. ( This makes sense to me and it makes it easy for me to let them control the search result relevance ).

Here’s a simplified query:

SELECT
p.ProductID         AS ContentID
, p.ProductName     AS Title
, p.ProductCode     AS Subtitle
, 100               AS Rank
, p.ProductKeywords AS Keywords
FROM Products AS p
WHERE FREETEXT( p.ProductKeywords, @SearchPredicate )

I’m thinking something along the lines of replacing the RANK with:

, 200 - INDEXOF(@SearchTerm)            AS Rank

This “should” rank the keyword results by their relevance

I know INDEXOF isn’t a SQL command… but it’s something LIKE that I would like to accomplish.

Am I approaching this the right way?

Is it possible to do something like this?

Does this make sense?

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  1. Editorial Team
    Editorial Team
    2026-05-15T04:01:20+00:00Added an answer on May 15, 2026 at 4:01 am

    Based on what you have and your need not to modify existing structures, this, well, shows how lame SQL Server is at string manipulation, but it would work. Walking through the logic:

    DECLARE
      @ProductKeywords varchar(100)
     ,@SearchPredicate varchar(10)
    
    SET @ProductKeywords = 'The,quick,brown,fox,jumps,over'
    SET @SearchPredicate= 'fox'
    
    --  Where in the string your search value is
    print charindex(@SearchPredicate, @ProductKeywords)
    
    --  The string up through but not including your search string
    print left(@ProductKeywords, charindex(@SearchPredicate, @ProductKeywords))
    
    --  Remove the commas (your delimiter) from the above
    print replace(left(@ProductKeywords, charindex(@SearchPredicate, @ProductKeywords)), ',', '')
    
    --  This is how many characters are left
    print len(replace(left(@ProductKeywords, charindex(@SearchPredicate, @ProductKeywords)), ',', ''))
    
    --  This is how many delimiters you removed,
    --  = the number of words (minus one) from the "first" the found word was,
    --  = a weighting factor you can use
    print charindex(@SearchPredicate, @ProductKeywords) - len(replace(left(@ProductKeywords, charindex(@SearchPredicate, @ProductKeywords)), ',', ''))
    

    Replace @ProductKeyword with p.ProductKeywords and it should do the trick. (Please note that I have zero experience with the full-text query engine. It may or may not have an impact on this code.)

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