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Home/ Questions/Q 503893
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:26:26+00:00 2026-05-13T06:26:26+00:00

In my domain model I have following Classes.A ‘UserProfile’ has one ‘SecurityPrincipal’ class SecurityPrincipal{

  • 0

In my domain model I have following Classes.A ‘UserProfile’ has one ‘SecurityPrincipal’

class SecurityPrincipal{
 private String loginId;
 private String password;
 private Date registeredData;
 private int status;
}



class UserProfile {

private String name;
private String company;
private SecurityPrincipa principal

}

I want to get the sorted results of ‘UserProfile’ objects and it works fine for simple properties.Like

DetachedCriteria criteria=DetachedCriteria.forClass(UserProfile.class);     

criteria.addOrder(Order.asc("name");

But when I try to access properties of inner bean (SecurityPrincipal instance) like

criteria.addOrder(Order.asc("principal.status");

Hibernate gives the error:

Caused by:
org.hibernate.QueryException: could
not resolve property:
securityPrincipal.status of:
com.bigg.ibmd.usermanagement.model.UserProfile
at
org.hibernate.persister.entity.AbstractPropertyMapping.propertyException(AbstractPropertyMapping.java:44)
at
org.hibernate.persister.entity.AbstractPropertyMapping.toColumns(AbstractPropertyMapping.java:59)
at
org.hibernate.persister.entity.BasicEntityPropertyMapping.toColumns(BasicEntityPropertyMapping.java:31)

How can I sort my results by properties-of-a-property?

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T06:26:26+00:00Added an answer on May 13, 2026 at 6:26 am

    Try this:

    DetachedCriteria criteria=DetachedCriteria.forClass(UserProfile.class);         
    criteria.createAlias("principal", "p");
    criteria.addOrder(Order.asc("p.name"));
    

    I haven’t tried it, nor am I sure that it’s the nicest way, but I think it should work.

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