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Home/ Questions/Q 770687
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T18:32:14+00:00 2026-05-14T18:32:14+00:00

In my interpreter, code like the following x=(y+4)*z echo x parses and optimizes down

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In my interpreter, code like the following

x=(y+4)*z
echo x

parses and “optimizes” down to four single operations performed by the interpreter, pretty much assembly-like:

add 4 to y
multiply <last operation result> with z
set x to <last operation result>
echo x
  • In modern interpreters (for example: CPython, Ruby, PHP), how simplified are the “opcodes” for which are in end-effect run by the interpreter?

  • Could I achieve better performance when trying to keep the structures and commands for the interpreter more complex and high-level? That would be surely a lot harder, or?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T18:32:15+00:00Added an answer on May 14, 2026 at 6:32 pm

    In Python’s case, you can have it tell you the bytecode for a given function with the dis module.

    from dis import dis
    def foo():
        x=(y+4)*z
        print x
    
    dis(foo)
    

    gives you:

    2           0 LOAD_GLOBAL              0 (y)
                3 LOAD_CONST               1 (4)
                6 BINARY_ADD          
                7 LOAD_GLOBAL              1 (z)
               10 BINARY_MULTIPLY     
               11 STORE_FAST               0 (x)
    
    3          14 LOAD_FAST                0 (x)
               17 PRINT_ITEM          
               18 PRINT_NEWLINE       
               19 LOAD_CONST               0 (None)
               22 RETURN_VALUE        
    

    Some of that is extraneous (e.g. the LOAD_CONST and RETURN_VALUE at the end are for the implicit return None in foo()), but Python appears to push y and 4 onto the stack, add, push z, multiply, and write to x. Then it pushes x and prints

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