Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
In my Iphone app I give a button when pressed calls a specific number using the following function call and uses the native iphone call app.
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:call_url]];
where call_url is of the form tel://
Once the call is done, is there a way to restore and open my Iphone App as it was before calling ?
No. Your process has been terminated. You’ll have to depend on the user to start your app again and you have to restore the state yourself.